Diameter crosses the whole circle through its center; radius reaches from the center to the edge. Circumference is the distance around it, and area is the surface enclosed. Use the measurement at the surface relevant to the job.
If d is diameter and r is radius, r = d ÷ 2, circumference = π × d, and area = π × r². Circumference has length units; area has square units. For a pipe wrapper, use the diameter at the surface whose distance around you need.
A 12 in diameter gives a circumference of 12π ≈ 37.699 in. The pipe example displays this as 37 11/16 in at its selected fraction precision. That fraction is a rounded display, not an exact value of π.
Find the distance around a pipe
Find the distance around a round pipe or duct from its outside diameter.
Why pi?
The distance around a circle is about 3.14159 times its diameter. π supplies that number: diameter × π = circumference.
Try it · a 12 in. diameter
Use 2nd if Inch is above its key.
Start fresh
Press Clear entry, then Clear entry, then Select length units.C→C→LengthOutside diameter
Press 12, then inches, then Multiply.12→Inch→×Multiply by pi
Press Second, then Pi, then Equals.2nd→π→=
- Circumference · rounded to 1/16 in.37 and 11/16 inches
About 37.7 inches. Your fraction setting controls rounding.
Also useful for
Pipe insulation wraps, round duct, circular edging, tank bands and the outside distance around a post. Use the diameter at the surface you are measuring.
Remember
This is the distance around the pipe. Add any seam or overlap allowance separately.
From a diameter
Tap Diameter for the full width across the circle.1
Start a new calculation
Use 2nd if a unit is above its button.
Start fresh
Press Clear entry, then Clear entry.C→CPress the keys
Press Select length units.Length
Open Circle
Skip if this mode is already open. Skip Close if no mode is open.
- Press Close calculation mode, then Open Circle.Close→Circle
1. Find circumference
Diameter
Press 11, then inches, then Store diameter.11→Inch→DiameterComplete the value
Press Equals.=
- Example · Circumference34 and 9/16 inches
2. Read area
- Press Equals.=
Results in orderPress = to continue
- Example · Circle area95.03318 square inches
- Radius5 and 1/2 inches
- Circumference again34 and 9/16 inches
- Circle area95.03318 square inches
Keep in mind
The displayed fractions are rounded; calculations retain the underlying value.
From a radius
Tap Radius for half the width, then = to read diameter.1
Start a new calculation
Use 2nd if a unit is above its button.
Start fresh
Press Clear entry, then Clear entry.C→CPress the keys
Press Select length units.Length
Open Circle
Skip if this mode is already open. Skip Close if no mode is open.
- Press Close calculation mode, then Open Circle.Close→Circle
1. Find diameter
Radius
Press 8, then feet, then 4, then inches, then Store radius.8→Feet→4→Inch→RadiusComplete the value
Press Equals.=
- Example · Diameter16 feet 8 inches
2. Read circumference
- Press Equals.=
- Example · Circumference52 feet 4 and 5/16 inches
3. Read area
- Press Equals.=
Results in orderPress = to continue
- Example · Circle area218.1662 square feet
- Diameter again16 feet 8 inches
- Circumference52 feet 4 and 5/16 inches
- Circle area218.1662 square feet
Keep in mind
The displayed fractions are rounded; calculations retain the underlying value.
Use pi in arithmetic
Multiply diameter by π to find circumference.2
Start a new calculation
Use 2nd if a unit is above its button.
Start fresh
Press Clear entry, then Clear entry.C→CPress the keys
Press Select length units.Length
Calculate
Diameter
Press 2, then feet, then Multiply.2→Feet→×Enter pi
Press Second, then Pi.2nd→πComplete the value
Press Equals.=
- Example result6 feet 3 and 3/8 inches
Display assumptions
Keep the guide beside your calculation.
These examples are built into Figure. Open Help while you calculate, then return to the same guide and reading position.
See Help in Figure →